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3x^2+0.12x-0.0036=0
a = 3; b = 0.12; c = -0.0036;
Δ = b2-4ac
Δ = 0.122-4·3·(-0.0036)
Δ = 0.0576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.12)-\sqrt{0.0576}}{2*3}=\frac{-0.12-\sqrt{0.0576}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.12)+\sqrt{0.0576}}{2*3}=\frac{-0.12+\sqrt{0.0576}}{6} $
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